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3a^2-15a=198
We move all terms to the left:
3a^2-15a-(198)=0
a = 3; b = -15; c = -198;
Δ = b2-4ac
Δ = -152-4·3·(-198)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-51}{2*3}=\frac{-36}{6} =-6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+51}{2*3}=\frac{66}{6} =11 $
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